A capacitor is charged with a battery and energy stored is u.after disconnecting vattery another capacitor of same capacity is connected in.parallel with it.the energy stored in each capacitor is
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Final Answer : U/4
STEPS:
1) Initially, Let the charge on capacitor be Q.
Then,
Energy Stored : Q^2/2C
2) After disconnecting the battery and connecting other identical capacitor parallel to it.
Now, Charge will flow in such a way that total charge is Q and potential difference across both capacitor remains same.
Hence,
Potential difference across each capacitor,
V = Q/2C
3) Then, Energy in each capacitor :
1/2C V^2
=>( 1/2 )C * (Q/2C)^2
=> (1/4 )* (1/2 Q^2/C)
=> 1/4U
Hence, Energy Stored in each capacitor becomes U/4 .
STEPS:
1) Initially, Let the charge on capacitor be Q.
Then,
Energy Stored : Q^2/2C
2) After disconnecting the battery and connecting other identical capacitor parallel to it.
Now, Charge will flow in such a way that total charge is Q and potential difference across both capacitor remains same.
Hence,
Potential difference across each capacitor,
V = Q/2C
3) Then, Energy in each capacitor :
1/2C V^2
=>( 1/2 )C * (Q/2C)^2
=> (1/4 )* (1/2 Q^2/C)
=> 1/4U
Hence, Energy Stored in each capacitor becomes U/4 .
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