Question

A car moving on a straight line road accelerates from a speed of 4.1 m per second to a speed of 6.9 m per second in 5.0 seconds then its average acceleration is

Answer 1

a = (v-u) /t
a= (6.9-4.1)/5
=2.8/5
=
$0.56\frac{m}{s {}^{2} }$