Question

A capacitor of 0.75 muF is charged to a voltage of 16 V. What is the magnitude of the charge on each plate of the capacitor ?

Answer 1

Answer:

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Answer 2

Answer:

The magnitude of the charge on each plate of the capacitor is 12 ×10⁻⁶c or 12μc.

Explanation:

Charge on each capacitor is given as,

$Q=CV$       (1)

Where,

Q=charge on each plate of the capacitor

C=capacity of the capacitor

V=potential difference across the plates of the capacitor

From the question we have,

C=0.75μF=0.75×10⁻⁶F

V=16v

By substituting the value of C and V in equation (1) we get;

$Q=0.75\times 10^-^6\times 16=12\times 10^-^6=12\mu c$

Hence,  the magnitude of the charge on each plate of the capacitor is  12 ×10⁻⁶c or 12μc.