Question

A capacitor of capacitance 10^2/π mewF is connected across a 220V.50Hz Ac mains .the capacitive reactance is what?

a)400ohms
b)500
c)300
d)100​

Answer 1

Answer:

The Capacitive Reactance of the Capacitor is 100 ohms.

Explanation:

Given Parameters:
Capacitance (C) = $\frac{10^{2} }{\pi }$ μF = $\frac{10^{2} }{\pi }*10^{-6} = \frac{10^{-4} }{\pi }$ F

Voltage (V) = 220 V

Frequency ( f) = 50 Hz

To Be Calculated :

The Capacitive Reactance

Solution:

The formula for the impedance of the Capacitor or Capacitive Reactance is given by,

$\\X_{c} = \frac{1}{2\pi fC}$

where $X_{C}$ is the Capacitive Reactance, f is the frequency and C is the value of the Capacitance of the Capacitor.

We Calculate,

$2\pi fC = 2\pi *50 * \frac{10^{-4} }{\pi } = 10^{-2}$

Putting all the values in the equation, we have

$\\X_{c} = \frac{1}{2\pi fC} = \frac{1}{10^{-2} }= 10^{2} = 100$

Therefore, the Capacitive Reactance of the Capacitor is 100 ohms.

So, The correct option is (d) 100 ohms.

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