Question

a capacitor of capacitance 1uf is charged to a potential difference of 1 V .it is connected in parallel to an inductor of inductance 10 to the power -3 H .the maximum current that flows in the circuit has valve ​

Answer 1

Answer:

energy conservation 1/2cv^2=1/2LI^2

Explanation:

Answer 2

Answer: 1mA

Explanation:Time period of the oscillator, T=2πLC√=2π10−3×10−6−−−−−−−−−−√=2π×10−92/ sec

So the angular frequency, ω=1092 /rad/s

Maximum current in the circuit,

Imax=Q0ω=CVω=10−6×1×1092/=10−32/ A=1032/ mA=(1000)1/2 mA