Question

A capacitor of capacitance 2 mF, is charged to a potential of 10 V. The capacitor is now connected to an identical capacitor charged to a voltage 20 V such that the plates of same polarity are connected together. The loss of energy in redistribution of the charges is​

Answer 1

Explanation:

Given :    C=10μF=10−5F                V=10 volts

Energy stored      E=21CV2

∴   E=21×10−5×102=5×10−4 J

⟹   E=500μJ

Answer 2

Answer:

0.05J

Explanation:

hope this helps you..