Question

A capacitor of capacitance 50 micro farads is charged to a potential difference of 200 Volts. Find out energy stored in the condenser

Answer 1

Answer:

1J

Explanation:

energy stored in a capacitor= $\frac{1}{2} CV^{2}$

                                               = 0.5 x 50 x $10^{-6}$ x $200^{2}$

                                               = 1J.

hope this helped :)

Answer 2

Answer:

A capacitor of capacitance 50 microfarads is charged to a potential difference of 200 Volts, the energy stored in the capacitor is $1J$

Explanation:

• A capacitor is used to store charge

• The electrical potential energy is stored in a capacitor

• For a capacitor with capacitance (C) and potential difference across the battery (V), the energy stored is

        $U=\frac{1}{2}CV^{2}$

From the question, we have

the capacitance of the capacitor    $C=50*10^{-6}F$

the voltage across the battery $V=200v$

put the values given,

the energy stored in the capacitor is

$U=\frac{1}{2}*50*10^{-6} *(200^{2} )$

⇒  $U=1 J$