Question

A capacitor of capacitance 6uf, is connected with an emf source 3v .electrostatic energy stored in the capacitor is

Answer 1

Electrostatic energy stored in the capacitor will be $27\times 10^{-6}J$

Explanation:

We have given capacitance of the capacitor $C=6\mu F=6\times 10^{-6}F$

It is given that capacitor is connected with an emf of 3 volt

So potential difference V = 3 volt

We have to fond the electrostatic energy stored in the capacitor

Energy stored in the capacitor is given by $E=\frac{1}{2}CV^2$

So energy will be equal to $E=\frac{1}{2}\times 6\times 10^{-6}\times 3^2=27\times 10^{-6}J$

So electrostatic energy stored in the capacitor will be $27\times 10^{-6}J$

Learn more

https://brainly.in/question/14236131