A capacitor of capacitance C has distance between plate d .A very thin mesh wire is placed .calculate new capacitance ?
Answers
Answered by
0
Answer:
1.00
Explanation:
m
x
=
N
D
d(
C
1
) =
K
m
ε
0
A
dx
=
Kε
0
A(1+
N
m
)
dx
=
Kε
0
A(1+
D
x
)
dx
C
eq
1
=∫d(
C
1
)=∫
0
D
Kε
0
A(D+x)
Ddx
C
eq
1
=
- Kε
0
A
D
ln2
C
eq
=
Dln2
Kε
0
A
.
Therefore α=1.
Answered by
0
Answer:
Answer:
1.00
Explanation:
m
x
=
N
D
d(
C
1
) =
K
m
ε
0
A
dx
=
Kε
0
A(1+
N
m
)
dx
=
Kε
0
A(1+
D
x
)
dx
C
eq
1
=∫d(
C
1
)=∫
0
D
Kε
0
A(D+x)
Ddx
C
eq
1
=
Kε
0
A
D
ln2
C
eq
=
Dln2
Kε
0
A
.
Therefore α=1.
Similar questions