If a capillary tube is tilted to 45 degree and 60 degree from vertical then ratio of length of l1 and l2 of liquids columns in it will be
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Answer:
1:√2
Explanation:
The expression for the capillary rise in a tube is given by,
H =
ρgr
2Tcosθ
where θ is the contact angle and not the angle of tilt.
Thus, for all parameters constant,
at 60
o
l
1
=Hcos60
0
= H/2
At 45
o
l
2
=Hcos45
0
= H/
2
Therefore the ratio of the 2 lengths is given by,
l
1
/l
2
=
2
1
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