Physics, asked by H3lios, 6 months ago

A capacitor of capacitance C is charged by a battery of P.D. V1 . Energy stored by the capacitor is E1 . The battery is then removed, and an identical uncharged capacitor is connected across the first capacitor. Energy stored by any one capacitor now is E2 . Find E1 : E2 .

Answers

Answered by NishantRaj7
1

Answer:

capacitor of capacitance C is charged by a battery of P.D. V1 . Energy stored by the capacitor is E1 . The battery is then removed, and an identical uncharged capacitor is connected across the first capacitor. Energy stored by any one capacitor now is E2 . Find E1 : E2 .

Explanation:

6uF capacitor is charged by a 300V supply. It is then disconnected from the supply and is connected to another uncharged 3uF capacitor. How much electrostatic energy of the first capacitor is lost in the form of heat and the electr900 pF capacitor is charged by 100 V source. Calculate the electrostatic energy stored in the

capacitor? The capacitor is then disconnected from the source and connected to another

uncharged 900 pF capacitor. Find the common potential of the system?

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