Physics, asked by racharla2886, 11 months ago

A capacitor of capacitance c is charged to a potential v from a cell and then isolated a xapacitor c is then charged from co discharged and charged again

Answers

Answered by knjroopa
0

Answer:

Explanation:

Given A capacitor of capacitance c is charged to a potential v from a cell and then isolated a capacitor c is then charged from co discharged and charged again

Now we know that potential of C on first charge

V1 = CoVo / (C + Co)

Now on second charging we get

V2 = CoV1 / (C + Co)

     = (Co / C + Co)^2 Vo

Similarly after n th charging we get

Vn = (Co / C + Co)^n Vo

(V o/ Vn)^1/n = Co + C / Co

C = Co [(Vo / v)^1/n – 1]

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