IF 3x+4y=16 and xy=4; find the value of 9x^2+16y^2
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( 3x + 4y ) = 16
= ( 3x + 4y )² = 16 ²
= 9x² + 16y² + 24xy = 256
= 9x² + 16y² + 24 × 4 = 256
9x² + 16y² = 256 - 96
9x² + 16y² = 160 Ans.
= ( 3x + 4y )² = 16 ²
= 9x² + 16y² + 24xy = 256
= 9x² + 16y² + 24 × 4 = 256
9x² + 16y² = 256 - 96
9x² + 16y² = 160 Ans.
aroushpotterhead15:
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answer is 160 hope it's helps u
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