A capacitor of capacitance C1 is charged to a potential V and then connected in parallel to an uncharged capacitor of capacitance C2. The final potential difference across each capacitor will be
Answers
Answered by
15
Answer:
Charge on first capacitor = q1 = C1V
Charge on second capacitor =q2 = 0
When they are connected, in parallel the total charge
q=q1+q2 therefore q= C1V and capacitance C= C1+C2
Let V be the common potential difference across each capacitor. then q = CV.
Therefore the final potential difference accross each capacitor will be
V'= q/C= C1V/C1+C2
Similar questions
Accountancy,
6 months ago
Social Sciences,
6 months ago
Science,
1 year ago
Social Sciences,
1 year ago
Social Sciences,
1 year ago