Physics, asked by krishiganesh, 1 year ago

A capacitor of capacitance C1 is charged to a potential V and then connected in parallel to an uncharged capacitor of capacitance C2. The final potential difference across each capacitor will be​

Answers

Answered by qwtiger
15

Answer:

Charge on first capacitor = q1 = C1V

Charge on second capacitor =q2 = 0

When they are connected, in parallel the total charge

q=q1+q2 therefore q= C1V  and capacitance C= C1+C2

Let V be the common potential difference across each capacitor. then q = CV.

Therefore the final potential difference accross each capacitor will be

V'= q/C= C1V/C1+C2

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