A capacitor of capacity 2muF is charged to 100 V. What is the heat generated when this capacitor is connected in parallel to n another capacitor of same capacity?
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Answer:
The answer of this question is 1.25*10^9 C^2/F.
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Heat generated for n capacitors in parallel will be , 0.01*n*mFV
•) Let, capacitance of the capacitor be C , heat energy generated be H and voltage applied be V.
•) Now , When n capacitors are in parallel then their total capacitance say C' will be :
C' = C + C + C +------------n
C' = nC
•) Now , we know ,
H = ½C*V^½
Here, V = 100V , C'= 2muF*n
Hence ,
H = ½*n*2muF*10000V
H = 10000*n*m*10^-6 FV
H = 0.01n*mFV
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