n identical capacitors are connected in parallel to a potential difference V. These capacitors are then reconnected in sereis, their charges being left undisturbed. The potential difference obtained is
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n identical capacitors are connected in parallel to a potential difference V. These capacitors are then reconnected in sereis, their charges being left undisturbed. The potential difference obtained is. ... In series, potentials of all capacitors will be added, so net potential will be NV.
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The potential difference obtained is - nV
The question states that firstly the capacitors are connected in parallel. The charge on each capacitor, when connected in parallel will be - Q = CV.
On connection in series, the capacitors will still have same charge Q as stated. Now, on series connection the total potential is sum of all the potentials.
Therefore new potential difference will be sum of potentials on n capacitors.
V total = Q/C of n capacitors
V total = nCV/C
V total = nV
Hence, total potential will be nV volts.