Question

An electron and a proton are projected with same velocity perpendicular to a magnetic field. (a) Which particle will describe the smaller circle? (b) Which particle will have greater frequency?

Answer 1

Answer:

proton have greater circle as compare to electron.

and electrons will have more frequency.

Explanation:

r = mv/ qB

Answer 2

The electron and proton will have different effect for frequency and area cover.

• The centripetal acceleration is mv²/r=qvB
• mv=qrB
• Frequency of revolving f=v/2πr
• f=qB/2πm
• f∝1/m
• So the electron having less mass than it will have the greater frequency.
• Now the radius depends upon the mass, as the proton having more mass then it will having the more radius of curvature.
• The electron will have less radius of curvature.