A car 20 m long travelling at 30m/sec overtakes another car 40 m long travelling at 20m/sec . the time taken by the first car to pass the second car is - (1) 2 sec (2) 4sec (3) 6 sec (4) 8 sec
Answers
Answer:
(3) 6 sec
Explanation:
Solving it with the help of relative velocity
Assuming the second car at rest the velocity of the first car w.r.t. the second car = 30 - 20 = 10 m/s
Now the first car has to travel with this velocity (10 m/s), a total distance equal to the length of the second car and the length of the first car to overtake it.
Thus the time taken by the first car to overtake the second car
= disptance/speed
= (20+40)/10
= 6 sec
Answer:
the time taken by the first car to pass the second car is 6 Sec
Explanation:
A car 20 m long travelling at 30m/sec overtakes another car 40 m long travelling at 20m/sec . the time taken by the first car to pass the second car is
Let sat T sec is taken by first car to pass second car
then distance covered by first car in T sec = Distance Covered by second car + length of second car + Length of First Car
=> distance covered by first car in T sec = Distance Covered by second car + 40 + 20
=> distance covered by first car in T sec = Distance Covered by second car + 60
distance covered by first car in T sec = 30T m
Distance Covered by second car in T sec = 20T m
=> 30T = 20T + 60
=> 10T = 60
=> T = 6
the time taken by the first car to pass the second car is 6 Sec