a car accelarete uniformaly from 18 km/he to 36 km/hr in 5 sec calculate accelration
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acceleration = [tex] a= \frac{v-u}{t} \\ v = 36 km/hr = 10 m/s \\ u= 18 km/ hr = 5 m/s \\ t = 5sec
\\ a = \frac{10-5}{5} = 1 m/s^{2}[\tex]
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\\ a = \frac{10-5}{5} = 1 m/s^{2}[\tex]
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Answered by
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Hiiii dear here is your answer....
This answer is verified ✅✅
Given,
u = 18km/hr ------>18×5/18m/s--->5 m/s
v = 36km/hr---->36×5/18---->10m/s
t = 5 s
a = 5/5
a= 1 m/s^2
Hope it will help you.....
This answer is verified ✅✅
Given,
u = 18km/hr ------>18×5/18m/s--->5 m/s
v = 36km/hr---->36×5/18---->10m/s
t = 5 s
a = 5/5
a= 1 m/s^2
Hope it will help you.....
RadhaG:
superb
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