a car accelerate uniform by from 20km/h to 40km/h in 5 sec. calculate (i)the acceleration
(i ) the distance covered by car in that time.
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Hello
__________________________
Here
u = 20 km / h = 5.5 m/s
v = 40 km / h = 11.1 m/s
t = 5 seconds
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v = u + at
a = v-u/t
a = 11.1-5.5/5
= 5.6/5
= 1.12 m/s²
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v² - u² = 2as
(11.1)² - (5.5)² = 2 x 1.12 x s
123.21 - 30.25 = 2.24 x s
92.96 = 2.24 x s
s = 92.96/2.24
s = 41.5 m
_________________________
__________________________
Here
u = 20 km / h = 5.5 m/s
v = 40 km / h = 11.1 m/s
t = 5 seconds
_________________________
v = u + at
a = v-u/t
a = 11.1-5.5/5
= 5.6/5
= 1.12 m/s²
_________________________
v² - u² = 2as
(11.1)² - (5.5)² = 2 x 1.12 x s
123.21 - 30.25 = 2.24 x s
92.96 = 2.24 x s
s = 92.96/2.24
s = 41.5 m
_________________________
Aerrika:
thanks bro.
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