Question

a car accelerate uniformly from 18 km/ hr to 36 km/hr in 5 sec the accelerating is

Answer 1

Hi.

Here is your answer---

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Initial speed(u) = 18 km/hr.
                         = 18 x (5/18) m/s               [ Changing into m/s ]
                         = 5 m/s
Final speed(v) = 36 km/hr.
                        = 36 x (5/18) m/s                [ Changing into m/s ]
                        = 10 m/s
Time(t) = 5 seconds.

Using the formula,
      Acceleration(a) = (v-u)/t
                               = (10-5)/5
                               = 5/5
      Acceleration   = 1 m/s^-2
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Thus, acceleration produced by the Car is 1 m/s^-2

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Hope it helps.

Have a nice day.

Answer 2

Given :-

• If a car accelerates uniformly from 18 km/hr to 36 km/hr in 5 seconds

To Find :-

• Acceleration

Solution :-

1 km/h = 5/18 m/s

18 km/h = 18 × 5/18

18 km/h = 5 m/s

36 km/h = 36 × 5/18

36 km/h = 2 × 5

36 km/h = 10 m/s

Now,

$\boxed{\sf{Acceleration = Final\: velocity - Initial\: velocity/Time}}$

a = 10 - 5/5

a = 5/5

a = 1/1

a = 1

Therefore

Acceleration is 1 m/s²