a car accelerated uniformly from 36km/hr to 54km/hr in 10 sec. find the acceleration
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Answered by
3
u=36km/h
=10m/s
v=54km/h
= 15 m/s
v=u+at
15=10+a×10
15-10=10a
a=.5 m/s*2
=10m/s
v=54km/h
= 15 m/s
v=u+at
15=10+a×10
15-10=10a
a=.5 m/s*2
dulaniaman:
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Answered by
1
Hello mate here's ur answer.... hope it helps you☺️☺️☺️
initial velocity(u)=36km/hr= 10m/s
final velocity(v)=54km/hr= 15m/s
time (t)=10sec
acceleration(a)= (v-u)/t
=15-10/10
=5/10 = 0.5 m/s^2
initial velocity(u)=36km/hr= 10m/s
final velocity(v)=54km/hr= 15m/s
time (t)=10sec
acceleration(a)= (v-u)/t
=15-10/10
=5/10 = 0.5 m/s^2
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