Question

a car accelerates along a straight road from rest to 50 km/hr in 5 s. what is the magnitude of its average acceleration?

Answer 1

a= V/t

(V in m/s )

V = 50*1000/3600

V= 13.88

now,

a = 13.88/5

a= 2.77 m/s^2

Answer 2

Answer:

Concept:

The change of an object's velocity with respect to time is called acceleration in mechanics. The term "acceleration" refers to a quantity that is measured in dimensions (in that they have magnitude and direction). The direction of an item's acceleration is determined by the position of the net force acting on it. Newton's Second Law describes the degree of an object's acceleration.

Given:

A automobile accelerates from 0 to 50 km/hr in 5 seconds on a straight route.

Find:

find what is the magnitude of its average acceleration?

Answer:

The rate at which the airspeed changes is referred to as average acceleration. To calculate the average acceleration of something, we divide the change in velocity by the elapsed time. The length of a vector equals its magnitude. It follows the same path as the vector. As a result, the magnitude of acceleration matches the acceleration vector's magnitude, and the direction equals the velocity vector's direction.

$a=\frac{v}{t}$

$V$  $in$  $m/s$

$V=\frac{50*1000}{3600}$

$V= 13.88$

now,

$a=\frac{13.88}{5}$

$a= 2.77 m/s^2$

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