a car accelerates at a constant rate so as to change its velocity in 5s from 10m/s to 25m/s on a highway. what is the acceleration and how far does the car go in this time interval?
Answers
Answered by
1
u=10m/s
v=25m/s
t=5s
a=v-u/t
a=25-10/5
=3 m/square
v=25m/s
t=5s
a=v-u/t
a=25-10/5
=3 m/square
Answered by
0
acceleration=(25-10)/5=1ms^-1
distance=ut+1/2at^2
=(10*5)+1/2(1*5^2)
= 50+25/2
= 50+12.5
=62.5 m
this is the ans hope it's help you
distance=ut+1/2at^2
=(10*5)+1/2(1*5^2)
= 50+25/2
= 50+12.5
=62.5 m
this is the ans hope it's help you
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