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AC = BD ( Given )
AC - BC = BD - BC ( if equals are subtracted from equals then results are equal)
AB = CD ..
Hence, proved..
AC - BC = BD - BC ( if equals are subtracted from equals then results are equal)
AB = CD ..
Hence, proved..
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it is given that , AC = BD
From the figure,
AC = AB + BC
BD = BC + CD
⇒ AB + BC = BC + CD
According to Euclid's axiom, when equals are subtracted from equals, remainders are also equal.
Subtracting BC both sides,
AB + BC - BC = BC + CD - BC
AB = CD
From the figure,
AC = AB + BC
BD = BC + CD
⇒ AB + BC = BC + CD
According to Euclid's axiom, when equals are subtracted from equals, remainders are also equal.
Subtracting BC both sides,
AB + BC - BC = BC + CD - BC
AB = CD
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