a car accelerates from 15 km/h to 60 km/h in 300 seconds. find the distance travelled by the car during this time.
plz solve this question.
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Answered by
12
Initial Speed of the Car(u) = 15 km/hr. = 4.167 m/s.
Final speed of the Car(v) = 60 km/hr. = 16.67
time taken by Car(t) = 300 seconds.
Using the Formula,
v - u = at
∴ 16.67 - 4.167 = a × 300
∴ a = 0.04 m/s².
Now,
v² - u² = 2aS
∴ 16.67² - 4.167² = 2 × 0.04 × S
∴ S = 3256.56 m.
∴ S = 3.256 km.
Hope it helps.
Answered by
8
Initial Speed of the Car(u) = 15 km/hr. = 4.167 m/s.
Final speed of the Car(v) = 60 km/hr. = 16.67
time taken by Car(t) = 300 seconds.
Using the Formula,
v - u = at
∴ 16.67 - 4.167 = a × 300
∴ a = 0.04 m/s².
Now,
v² - u² = 2aS
∴ 16.67² - 4.167² = 2 × 0.04 × S
∴ S = 3256.56 m.
∴ S = 3.256 km
Final speed of the Car(v) = 60 km/hr. = 16.67
time taken by Car(t) = 300 seconds.
Using the Formula,
v - u = at
∴ 16.67 - 4.167 = a × 300
∴ a = 0.04 m/s².
Now,
v² - u² = 2aS
∴ 16.67² - 4.167² = 2 × 0.04 × S
∴ S = 3256.56 m.
∴ S = 3.256 km
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