Question

A car accelerates from 36 km/h to 90km/h in5s on a straight rod.what was it's acceleration in m/s and how far did it travel in this time.

Answer 1

Answer:

acceleration=3 m/s²

distance=87.5 m

Explanation:

initial velocity=36 km/h

                      =10 m/s

final velocity=90 km/h

                    =25 m/s

time taken= 5 sec

acceleration=change in velocity / time

a=v-u/t

 =25-10/5

  =15/5

   =3 m/s²

In order to find the distance, we have to use the second law of motion that is

S=ut+1/2at²

  =10×5+1/2×3×25

  =87.5 m

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Answer 2

Answer:

v=25m/s.

s=87.5m

Explanation:

u=36km/hr convert into m/s.

u=36000/3600=10m/s

u=10m/s.

v=90km/hr convert into m/s.

v=90000/3600=25m/s

v=25m/s.

v=u+at

a=25-10/5

a=3m/s^2

s=ut+1/2at^2

s=10*(5)+1/2*3*(5)^2

s=87.5m

Hope it helps you

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