a car accelerates from 6m/s to 16m/d in 10s .calculate accelaration and distance coverded by the car that time.
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Answered by
4
Initial velocity (u) =6m/s
Final velocity (v) =16m/s
Time(t)=10sec
Acceleration (a) =?
a=v-u/t
=16-6/10
=10/10
=1
Acceleration (a) =1m/s
Distance =?
s=ut+1/2at^2
=6×10+1/2×1×10^2
=60+1/2×100
=60+1×50
=60+50
=110
Therefore...distance =110m
Hope it helps!!!! ✌️
Final velocity (v) =16m/s
Time(t)=10sec
Acceleration (a) =?
a=v-u/t
=16-6/10
=10/10
=1
Acceleration (a) =1m/s
Distance =?
s=ut+1/2at^2
=6×10+1/2×1×10^2
=60+1/2×100
=60+1×50
=60+50
=110
Therefore...distance =110m
Hope it helps!!!! ✌️
Answered by
0
Answer:
the answer is 110m
Explanation:
acc v-u /y
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