a car accelerates from 6ms1 to 16ms1 in 10 sec.calculate the acceleration & the distance covered by the car
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a=(v2-v1)÷t
=16-6÷10
=1m/s^2
S=ut+1/2at^2
=6×10+1/2×1×10×10
=60+50=110m
=16-6÷10
=1m/s^2
S=ut+1/2at^2
=6×10+1/2×1×10×10
=60+50=110m
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