A car accelerates from rest at a constant rate 'A'for sometime, after which it retards at a constant rate 'B' to come to rest . if the total time lapse is T second, evaluate the maximum velocity reached and the total distance travelled in terns of A,B and T.
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Explanation:
Hey,
Let car start moving in time t1 and retards at time t2; total time take by the car to reach the maximum velocity is【 T = t1+t2】
Condition:1_
when car is moving; u=0
V=u+at => v=At1 eqn…1
Condition:2_
When car is start retarding at time t2,
Since,v=u+at so that u=v-Bt2=> 0=v-Bt2 =>v=Bt2 eqn….
eqn..1=eqn..2 => At1 = Bt2 => t2=At1/B
Total time taken by the car to reach maximum velocity T =t1+t2= t1+At1/B =t1 (1+A/B)
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