Question

A car accelerates from rest at a constant rate a for some
time, after which it decelerates at constant rate b to
come to rest. If the motion is along a straight line then
the ratio of average speeds in accelerated to decelerated
one
motion will be:
​

Answer 1

Answer:

D

Explanation:

Let maximum velocity=v

Now,v=0+αt

1

Similarly, 0=v−βt

2

From the above equations we get,

t

1

=

α

v

&t

2

=

β

v

t

1

+t

2

=t=

α

v

+

β

v

⇒v=

α+β

αβ

t