a car accelerates from rest at a constant rate alpha for some time after which it decelerates at a constant rate beta . If the total time is t prove that maximum velocity reached is v=alpha×beta×t/alpha+beta and total displacement is s=alpha×beta^2/2(alpha+beta)
Answers
Answer:
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Explanation:
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Distance
The distance is the actual length of the path that the object travels.
Displacement
The displacement is the shortest distance between the initial position and the final position of the journey. For example, if an object goes in a circle and returns to its initial position, then its displacement is zero while its distance is not. In general, we say that distance is either greater than or equal to the displacement of an object. The displacement can never be smaller than the distance.
Velocity Formula
The velocity is the time rate of change of displacement. If ‘S’ is the displacement of an object in some time ‘T’, then the velocity is equal to, v = S/T. The units of velocity are m/s or km/hr.
Speed:
The speed is the time rate of change of the distance. If ‘D’ is the distance of an object in some time ‘T’, the speed is equal to, s = D/T. It has the same units as velocity. let us solve some examples, we will introduce the formulae as we go along.
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