a car accelerates from rest at a constant rate alpha for some time, after which it decelerates at a constant rate beeta and comes to rest. if the total time elapsed is t, the maximum velocity acquired by the car will be?
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For the first leg of the journey,
V = 0 + α t1
So V = α t1
for the second leg of journey of duration t - t1 :
0 = V - β (t - t1)
0 = α t1 - β t + β t1
t1 = β t / (α + β)
V = αt1 = α β t / (α + β )
V = 0 + α t1
So V = α t1
for the second leg of journey of duration t - t1 :
0 = V - β (t - t1)
0 = α t1 - β t + β t1
t1 = β t / (α + β)
V = αt1 = α β t / (α + β )
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