two jets are 2370 km apart and travelling toward each other, one at 720 km/hr and the other at 860 km/hr. how far does each travel before they pass
sweetysiri92:
answers are 1080km and 1290 km
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The scenario is something like this, A is first jet, B is second jet, P is point of crossing,
A-->.................................(d = 2370)..................................<-----B
velocity=720 (for first jet A) '''''''''[P]'''''''''' (for second jet B) velocity=860
Now say the jets fly for t seconds, before meeting at P,
So, distance covered by A = 720 * t
And distance covered by B = 860 * t
-> 720 * t + 860 * t = 2370
-> 1580 * t = 2370
So distance covered by A = 720 * 1.5 = 1080 km
And distance covered by B = 860 * 1.5 = 1290 km
Answer
1080 km, 1290 km
A-->.................................(d = 2370)..................................<-----B
velocity=720 (for first jet A) '''''''''[P]'''''''''' (for second jet B) velocity=860
Now say the jets fly for t seconds, before meeting at P,
So, distance covered by A = 720 * t
And distance covered by B = 860 * t
-> 720 * t + 860 * t = 2370
-> 1580 * t = 2370
So distance covered by A = 720 * 1.5 = 1080 km
And distance covered by B = 860 * 1.5 = 1290 km
Answer
1080 km, 1290 km
Answered by
0
relative speed of one with respect to the other= 720 +860 =1580
time taken to pass each other = 2370/1580 = 1.5 hr
distance travelled by first jet = 1.5 * 720 = 1080 km
distance travelled by t h esecond jet = 1.5 * 860 = 1290 km
time taken to pass each other = 2370/1580 = 1.5 hr
distance travelled by first jet = 1.5 * 720 = 1080 km
distance travelled by t h esecond jet = 1.5 * 860 = 1290 km
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