Question

A car accelerates from rest at a constant rate α for sometime and reaches maximum velocity . Then it decelerates at a constant rate β to come to rest . If total time elapsed is 't' , then the maximum velocity acquired by the car will be ,
A ) ( α+β ) t/ αβ
B ) ( αβ ) t / α+ β
C ) ( αβ ) t / α² + β²
D ) ( α² + β² ) t / αβ

Please answer with the reason . Spam answers will be reported immediately and best answer will be marked brainliest:)

Answer 1

Answer:

since acceleration is the slope in v-t graph..let maximum velocity be v

a=v/t1

t1=v/a...........(1)

similarly

t2=v/b..........(2)

adding 1 and 2

t1+t2=(v/a)+(v/b)

t=v(a+b)/ab

v=abt/(a+b).

.... here a is alpha ,b is beta

t is total time =t1+t2

where t1 is time in reaching from 0 to v

and t2 is time in reaching from v to 0

Answer 2

Answer:

Answer is here:-

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