Question

A car accelerates from rest with a constant acceleration α on a straight road. After gaining a velocity v, the car moves with the same velocity for some time. Then the car is decelerated to rest with a retardation β. If the total distance covered by the car is equal to S, the total time taken for its motion is​

Answer 1

Answer:

Let maximum velocity=v

Now,v=0+αt

1

Similarly, 0=v−βt

2

From the above equations we get,

t

1

=

α

v

&t

2

=

β

v

t

1

+t

2

=t=

α

v

+

β

v

⇒v=

α+β

αβ

t