a car accelerates from standing start and reaches a velocity if 18m/s after 6 seconds. calculate its acceleration
Answers
Answer:
Acceleration = Rate of change of velocity is known as the acceleration.
here, u=0, v=18m/s and t= 6 seconds
a =v-u/t.........( formula)
here, a is acceleration, v is final velocity and u is initial velocity.
therefore by substituting the values we get,
a=18-0/6
a=18/6
a=3 m/ s²
Therefore the acceleration of a car is 3 m/ s²
Given
Car starts from rest.
Final velocity of car = 18 m/s
Time = 6 seconds.
To find
Acceleration of car after 6 seconds.
Solution
As here, the car starts from rest so the initial velocity of car will be 0.
⇒ Initial velocity (u) = 0 m/s
⇒ Final velocity (v) = 18 m/s
⇒ Time (t) = 6 seconds.
Equation of motion used :
⇒ a = (v - u)/t
Putting values here :
⇒ a = (18 - 0)/6
⇒ a = 18/6
⇒ a = 3 m/s²
Therefore,
Acceleration of car = 3 m/s²
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Additional informations :
Derivation of the equation [a = (v - u)/t] :
We know equation of motion :
⇒ v = u + at
⇒ at = v - u
⇒ a = (v - u)/t
More equations of motion :
⇾ v² - u² = 2as
⇾ s = ut + ½ at²
⇾ v - u = at