Question

A car accelerates unifomly from 5 m/s to 10 m/s in 10s.find its acceleration and displacement

Answer 1

Hii..
Here is your answer..

Solution:-
Initial velocity(u)=5m/s
Final velocity(v)=10m/s
Time(t) =10s
Acceleration(a)=?

$acceleretion = \frac{v - u}{t} \\ = > \frac{10 - 5}{10} \\ = > \frac{5}{10} \\ = > 0.5m \: per \: sec \: sq$
Acceleration=.5m/s^2

Now,
Displacement covered=?
We'll find it by using equation:-
$= > s = ut + \frac{1}{2} a {t}^{2} \\ = > s = 5 \times 10 + \frac{1}{2} \times 0.5 \times {10}^{2}$
$= > s = 50 + \frac{1}{2} \times 0.5 \times 100 \\ = > s = 50 + 0.5 \times 50 \\ = > s = 50 + 25 \\ = > s = 75$
So,
Displacement=75m

Hope it helps uh...✌️✌️✌️

Answer 2

✬ Acceleration = 0.5 m/s² ✬

✬ Displacement = 75 m ✬

Explanation:

Given:

• Uniform speed of car (u) = 5 m/s.
• Final speed of car (v) = 10 m/s.
• Time taken by car to reach final speed (t) = 10 seconds.

To Find:

• What is the acceleration and displacement ?

Formula to be used:

• v = u + at ( For acceleration )
• s = ut + 1/2at² ( For displacement )

Solution: Putting the given values on first formula to find acceleration of car.

$\implies{\rm }$ v = u + at

$\implies{\rm }$ 10 = 5 + a $\times$ 10

$\implies{\rm }$ 10 = 5 + 10a

$\implies{\rm }$ 10 – 5 = 10a

$\implies{\rm }$ 5 = 10a

$\implies{\rm }$ 5/10 = a

$\implies{\rm }$ 1/2 = a

$\implies{\rm }$ 0.5 m/s² = a

Hence, the acceleration of the car is 0.5 m/s².

______________________________

Now, Using the second formula to find displacement of car.

$\implies{\rm }$ s = ut + 1/2at²

$\implies{\rm }$ s = 5 $\times$ 10 + 1/2 $\times$ 0.5 $\times$ (10)²

$\implies{\rm }$ s = 50 + 1/2 $\times$ 5/10 $\times$ 100

$\implies{\rm }$ s = 50 + 1/2 $\times$ 5 $\times$ 10

$\implies{\rm }$ s = 50 + 5 $\times$ 5

$\implies{\rm }$ s = 50 + 25

$\implies{\rm }$ s = 75 m

Hence, the displacement of the car is 75 m.