Question

A car starts from rest and moves along the x axis with constant acceleration 5m/s^2 for 8 seconds . if it then continues with constant velicity what distance will the car cover in 12 seconds since it started from the rest

Answer 1

u = 0, a = 5 m/s^2, t = 8 s

v = u + at = 40 m/s

s = ut + 1/2 at^2

s = 5 * 32 = 160 m ( during acceleration)

s = vt = (12-8) * 40 = 160 m ( constant velocity)

Total distance = 320 m