Question

A car travelling at 60km/hr overtakes another car travelling at 42km/hr assuming each car to be 5.0 m long find the time taken during the overtake and find distance used for the overtake

Answer 1

Hii..
Here is your answer..

Solution:-
60km/h is equal to
$= > 60 \times \frac{5}{18}$
$= > \frac{50}{3} m \: per \: sec$
42km/h is equal to
$= > 42 \times \frac{5}{18} \\ = > \frac{70}{6} m \: per \: sec$
Two car are in same direction so the variable velocity will be=
$= > \frac{50}{3} - \frac{70}{6} \\ = > \frac{100 - 70}{6} \\ = > \frac{30}{6} \\ = > 5m \: per \: sec$
Speed=5m/s
Distance=10m
So,
Time =D/S
$= > \frac{10}{5} = 2sec$
Distance travelled by travelled by car in 2 seconds= velocity× 2 sec
$= > \frac{50}{3} \times 2 \\ = > \frac{100}{3}$
$= > 33.34m$
Total distance=5m+33.34m
$= > 38.34m$
Hope it helps uh...✌️✌️✌️