A car accelerates uniformly from 18 km 36 km/h in 2 seconds. Calculate a. the acceleration b. the distance covered by the car in that time. Pls give the full explanation..I will mark u as the brain liest
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Answer:
Given parameters
Time taken (t) = 5 sec
Initial velocity (u) =18 km/hour
u=18×100060×60s
u = 5 m/s
Final velocity (v) =36km/hour
v=36×100060×60s
v =10 m/s
We need to calculate acceleration and distance travelled
We know that
acceleration a = (v – u)/t
Substituting the given values in the above equation we get,
a = (10 – 5)/5
a =5/5
a = 1 m/s2
We know that distance travelled is calculated by the formula
Distance travelled S = u t + (1/2) a × t2
Substituting the given values in the above equation we get,
S = 5 × 5 + (1/2) × 1 × 52
S = 25 + (1/2) × 25
S = 25 + 12.5
S = 37.5 m
Hence
acceleration a =1 m/s2
Distance travelled S =37.5 m
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