A car accelerates uniformly from 18 km h-¹ to 36 I'm h-¹ in 5s. Calculate:- (I) the Acceleration (II) Distance covered by the car in that time. PLEASE ANSWER, IT IS VERY URGENT
Answers
Answered by
1086
Given,
(I) Calculating Acceleration
As, we know
Thus, acceleration is
(II) Calculating Distance Travelled
As, we know
Thus, distance travelled is
Additional Information
- Rate of Change of Distance is known as Speed.
- The speed of body which is applied in beginning is known as Initial Speed and is denoted by u.
- The speed of body which is acquired after the body starts Moving is know as Final Speed and is represented by v.
- Rate of change of Velocity is known as Acceleration.
- Negative Acceleration is known as Retardation.
Important Formulas
Vamprixussa:
Splendid !
Answered by
109
Explanation:
Acceleration=change in velocity/ time
Change in velocity=36-18=18km/h=5m/s
time=5s
acceleration=5/5=1m/s2
equation of motion,
s=ut+(1/2)at2
u=18 km/h=5 m/s
t=5s
a=1m/s2
s=(5*5)+(1/2*1*5*5)
s=25+12.5 i.e.,=37.5m
formula used:
change in velocity\time=acceleration
s=ut+(1/2) at2
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