Question

lf (2, k) is One solution of equation x+y+2=0, then what is the value of k?
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Answer 1

Given:

The equation given is x + y + 2 = 0

The solution of the equation = (2, k)

To find:

The value of k.

Solution:

If (2,k) is a solution of the equation then it must satisfy the equation.

So we will put the values in the equation, then we get:

2+ k + 2 = 0

4 + k= 0

Taking 4 on the other side we get:

k = -4

Therefore the value of k is -4.

Answer 2

Given : Equation is = x + y + 2 = 0 ………(1)

(2, k) is one solution of the above given equation .

To find: The value of k.

Solution:

It is given that (2,k) is a solution of the equation then it must satisfy the given equation.

Here, x = 2 and y = k

Now put these values in equation (1), we get:

x + y + 2 = 0

2 + k + 2 = 0

4 + k = 0

k = 0 - 4

k = - 4

Hence, the value of k is - 4.

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