Question

A car accelerates uniformly from 18 km h⁻¹ to 36 km h⁻¹ in 5 s. Calculate (i) the acceleration and (ii) the distance covered by the car in that time.

Answer 1

QuestioN :

A car accelerates uniformly from 18 km h⁻¹ to 36 km h⁻¹ in 5 s. Calculate (i) the acceleration and (ii) the distance covered by the car in that time.

GiveN :

• accelerates uniformly from 18 km h⁻¹ to 36 km h⁻¹ in 5 s.

To FiNd :

• Calculate the acceleration
• Calculate the distance covered by the car in that time.

ANswer :

$\bigstar$ The acceleration of the car is 1 m s⁻².

$\bigstar$ The distance covered is 37.5 m.

SolutioN :

Given that,

• $\sf u=18\:km\:h^-^1=5\:m\:s^-^1$

• $\sf v = 36\:km\:h^-^1=10m\:s^-^1\:and$

• $\sf t = 5\:s.$

i) we know that,

$\sf a = \dfrac{v-u}{t}$

$\sf \implies \dfrac{10m\:s^-^1-5\:m\:s^-^1}{5\:s}$

$\sf \implies 1\:m\:s^-^2$

ii) We have,

$\sf s=u\:t +\dfrac12at^2$

$\sf \implies 5\:m\:s^-^1 \times 5\:s + \dfrac12\times1\:m\:s^-^2\times [5\:s]^2$

$\sf \implies 25\:m + 12.5\:m$

$\sf \implies 37.5\:m$

∴Hence, The acceleration of the car is 1 m s⁻² and the distance covered is 37.5 m.

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Answer 2

Answer:

Here, is ur answers dear.

a = 1 meter per second square

s = 37.5 m

Explanation:

Hope it helps you dear｡◕‿◕｡