a car accelerates uniformly from 18 km/h to 36 km/h in 5 secs. calculate the acceleration and the distance covered by the car in that time
Answers
Answered by
5
Accleration,a=1m|s^2 and distance,s=25m
na2028:
u r wrong
s=37.5
Answered by
19
Initial velocity, u=18 km/hr
Final velocity ,V =36 km/hr
Time.t =5 secs
Acceleration ,a=v-u/t
=36-18/5
=18/5=3.6m/s²
distance= s
=v²-u²=2as
36²-18²=2×3.6×s
1296-324=7.2s
s=972/7.2
s =160mts
Final velocity ,V =36 km/hr
Time.t =5 secs
Acceleration ,a=v-u/t
=36-18/5
=18/5=3.6m/s²
distance= s
=v²-u²=2as
36²-18²=2×3.6×s
1296-324=7.2s
s=972/7.2
s =160mts
You r wrong to convert km per hour we need to multiply it by 5 and divide it by 18
oh yes!!! thanks
saw it afterwards
Similar questions