A car accelerates uniformly from 18 km h to 36km h in 10 sec calculate acceleration and distance cover by car in that time
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a=v-u/t
therefore,a=36-18/10
a=18/10=1.8m/s2
s=ut+1/2at whole square
s=18×10+1/2×1.8×10×10
s=180+1/2×180
s=180+90=270.
bro the car has travelled 270 m with a n acceleration of 1.8m/s2
therefore,a=36-18/10
a=18/10=1.8m/s2
s=ut+1/2at whole square
s=18×10+1/2×1.8×10×10
s=180+1/2×180
s=180+90=270.
bro the car has travelled 270 m with a n acceleration of 1.8m/s2
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