Question

9x+3y+12=0 ,18x+6y+24=0

Answer 1

9x=-12-3y
x=(-12-3y)/9

18x+6y+24=0
18 (-12-3y)+6y+24=0
-216-54y+6y+24=0
-192-48y=0
-48y=192
y=-192/48=-4
so y=-4
then,
x=(-12-3y)/9=[-12-(3×-4)]/12=(-12+12)/12=0/12=0
so x=0 ; y= -4

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Answer 2

Concept introduction:

A mathematical expression with an equals sign is referred to as an equation. Algebra is widely used in equations. When performing calculations but unsure of the precise amount, algebra is utilized. A lot of specialists, such as air traffic controllers, architects, computer programmers, and carpenters, employ equations on a daily basis.

Given:

The two equation given to us is

$9x+3y+12=0 \\18x+6y+24=0$

To find:

We have to find the value of $x$ and $y$.

Solution:

According to the problem,

$9x=-12-3y\\x=(-12-3y)/9$

$18x+6y+24=0\\18 (-12-3y)+6y+24=0\\-216-54y+6y+24=0\\-192-48y=0\\-48y=192\\y=-192/48=-4$

so $y=-4$

then,

$x=(-12-3y)/9=[-12-(3*-4)]/12=(-12+12)/12=0/12=0$

so $x=0 ; y= -4$

Final answer:

The final answer of the question is $x=0 ; y= -4$.

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