Question

a car accelerates uniformly from 18 km/ hour to 72 km per hour in 10 s. calculate the acceleration of the car ​

Answer 1

Answer:

Given parameters

Time taken (t) = 5 sec

Initial velocity (u) =18 km/hour

 

u=18×100060×60s

 

u = 5 m/s

Final velocity (v) =36km/hour

 

v=36×100060×60s

 

v =10 m/s

We need to calculate acceleration and distance traveled

We know that

acceleration a = (v – u)/t

Substituting the given values in the above equation we get,

a = (10 – 5)/5

a =5/5

a = 1 m/s2

We know that distance travelled is calculated by the formula

Distance travelled S = u t + (1/2) a × t2

Substituting the given values in the above equation we get,

S = 5 × 5 + (1/2) × 1 × 52

S = 25 + (1/2) × 25

S = 25 + 12.5

S = 37.5 m

Hence

acceleration a =1 m/s2

Distance travelled  S =37.5 m

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Answer 2

Answer:

0.0015KM/SEC

Explanation:

WE KNOW THE FORMULA FOR ACCELERATION=(CHANGE IN VELOCITY)/TIME

SO,

CHANGE IN VELOCITY=72KM/HOUR-18KM/HOUR

                                       =54KM/HOUR

SO,

ACCELERATION=CHANGE IN VELOCITY/TIME

                           =54KM/10*3600

                           =0.0015KM/SEC

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