A car accelerates uniformly from 18 km/hr in 5 second. Calculate the acceleration and the distance covered by the car
Answers
Answered by
14
initial velocity=18kmh-¹=5ms-¹
final velocity =0ms-¹
t=5sec
a=0-5/5
a=-1ms-²
negative sign shows retardation
2as=v²-u²
2×(-1)s=0²-5²
-2s=-25
s=12.5m
Hope it helps!
final velocity =0ms-¹
t=5sec
a=0-5/5
a=-1ms-²
negative sign shows retardation
2as=v²-u²
2×(-1)s=0²-5²
-2s=-25
s=12.5m
Hope it helps!
Answered by
3
Explanation:
ANSWER
Given,
u=18km/h=
60×60
18×1000
=5m/s
v=36km/h=
60×60
36×1000
=10m/s
t=5sec
acceleration, a=?
1st equation of motion,
v=u+at
10=5+5a
5a=5
a=
5
5
=1m/s
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