Question

The resistance per meter length of wire is 10ohm.if the resistivity of the material of the wire is 50*10-8ohm meters find the area of cross -section of the wire

Answer 1

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Answer 2

Answer:

Area, $A=5\times 10^{-8}\ m^2$

Explanation:

It is given that,

The resistance per meter length of wire is, $\dfrac{R}{l}=10\ \Omega$

Resistivity of the wire, $\rho=50\times 10^{-8}\ \Omega-m$

The resistance of a wire is given by :

$R=\rho\dfrac{l}{A}$

$\dfrac{R}{l}=\dfrac{\rho}{A}$

$A=\dfrac{\rho}{R/l}$

$A=\dfrac{50\times 10^{-8}}{10}$

$A=5\times 10^{-8}\ m^2$

Hence, this is the required solution for the area of cross section of the wire.